Bohr's theory states that the angular momentum \( L \) of an electron in the \( n \)-th orbit is quantized and can be calculated using the formula:
\[ L = \frac{n h}{2\pi}, \] where \( h \) represents Planck’s constant and \( n \) is the principal quantum number of the orbit.
For an electron occupying the 4th orbit (\( n = 4 \)), the angular momentum is:
\[ L = \frac{4h}{2\pi} = \frac{2h}{\pi}. \]
Answer: \(\frac{2h}{\pi}\)
Given below are two statements:
Statement (I) : The dimensions of Planck’s constant and angular momentum are same.
Statement (II) : In Bohr’s model, electron revolves around the nucleus in those orbits for which angular momentum is an integral multiple of Planck’s constant.
In the light of the above statements, choose the most appropriate answer from the options given below: