Bohr's theory states that the angular momentum \( L \) of an electron in the \( n \)-th orbit is quantized and can be calculated using the formula:
\[ L = \frac{n h}{2\pi}, \] where \( h \) represents Planck’s constant and \( n \) is the principal quantum number of the orbit.
For an electron occupying the 4th orbit (\( n = 4 \)), the angular momentum is:
\[ L = \frac{4h}{2\pi} = \frac{2h}{\pi}. \]
Answer: \(\frac{2h}{\pi}\)
| List I (Spectral Lines of Hydrogen for transitions from) | List II (Wavelength (nm)) | ||
| A. | n2 = 3 to n1 = 2 | I. | 410.2 |
| B. | n2 = 4 to n1 = 2 | II. | 434.1 |
| C. | n2 = 5 to n1 = 2 | III. | 656.3 |
| D. | n2 = 6 to n1 = 2 | IV. | 486.1 |