Question

A vernier callipers has 20 divisions on the vernier scale, which coincides with 19^th division on the main scale. The least count of the instrument is 0.1 mm. One main scale division is equal to ____mm.

• A. 1
• B. 0.5
• C. 2
• D. 5

Answer 1

The Correct Option is C

Given:
- 20 vernier scale divisions (VSD) correspond to 19 main scale divisions (MSD).
- The instrument's least count (L.C.) is \( 0.1 \, \text{mm} \).

Step 1: Relation Between VSD and MSD
From the provided data:

\[ 20 \, \text{VSD} = 19 \, \text{MSD}. \]

The value of one vernier scale division (1 VSD) is calculated as:

\[ 1 \, \text{VSD} = \frac{19}{20} \, \text{MSD}. \]

Step 2: Calculating the Least Count
The formula for the least count (L.C.) is:

\[ \text{L.C.} = 1 \, \text{MSD} - 1 \, \text{VSD}. \]

Substituting the value of 1 VSD into the formula:

\[ \text{L.C.} = 1 \, \text{MSD} - \frac{19}{20} \, \text{MSD} = \frac{1}{20} \, \text{MSD}. \]

Given that the least count is \( 0.1 \, \text{mm} \):

\[ 0.1 \, \text{mm} = \frac{1}{20} \, \text{MSD}. \]

To find the value of 1 MSD, multiply both sides by 20:

\[ 1 \, \text{MSD} = 2 \, \text{mm}. \]

Therefore, one main scale division is equivalent to \( 2 \, \text{mm} \).