Question:easy

A velocity-time graph is drawn for two different objects. They make \( 30^{\circ} \) and \( 45^{\circ} \) with the time axis. Then the ratio of their accelerations, \( a_1: a_2 \) is

Show Hint

Always remember that on any kinetic plotting graph:

• Slope of Displacement-Time curve \( = \) Velocity.

• Slope of Velocity-Time curve \( = \) Acceleration.
Updated On: Jun 7, 2026
  • 1:2
  • 2:3
  • \( \sqrt{3}:1 \)
  • \( 1:\sqrt{3} \)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Know what the slope of a v-t graph means.
On a velocity time graph, the slope of the line tells us the acceleration. This is because acceleration is how fast velocity changes with time, which is exactly rise over run on this graph.
Step 2: Turn an angle into a slope.
If a line makes an angle $\theta$ with the time axis, its slope is $\tan\theta$. So the acceleration of each object equals the tangent of its angle.
Step 3: Write acceleration for the first object.
The first line makes $30^{\circ}$ with the time axis: \[ a_1 = \tan 30^{\circ} = \frac{1}{\sqrt{3}} \]
Step 4: Write acceleration for the second object.
The second line makes $45^{\circ}$ with the time axis: \[ a_2 = \tan 45^{\circ} = 1 \]
Step 5: Form the ratio.
Divide the first acceleration by the second: \[ \frac{a_1}{a_2} = \frac{1/\sqrt{3}}{1} = \frac{1}{\sqrt{3}} \]
Step 6: State the answer.
So the accelerations are in the ratio: \[ \boxed{a_1 : a_2 = 1 : \sqrt{3}} \]
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