Step 1: Given Information
- Initial velocity, \( u = 49 \, \text{m/s} \) (upward)
- Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \) (acting downward)
- Final velocity at peak, \( v = 0 \, \text{m/s} \)
Step 2: Time to Reach Peak
Apply the kinematic equation \( v = u - gt \). Taking upward as positive and downward as negative for acceleration:
\[ 0 = 49 - 9.8 \cdot t \] Solving for \( t \):
\[ t = \frac{49}{9.8} = 5 \, \text{seconds} \] Thus, 5 seconds are required to reach the highest point.
Step 3: Total Flight Time
Assuming symmetrical trajectory, time up equals time down.
\[ \text{Total time} = 2 \times 5 = 10 \, \text{seconds} \]