List of top Physics Questions on Kinematics asked in AP EAPCET

If the minimum velocity of a projectile during its motion is \(40\,\text{m s}^{-1}\) and the ratio of its vertical and horizontal displacements at a time of \(2\,\text{s}\) is \(1:2\), then the angle of projection of the projectile is:

A body is falling freely under gravity from a height of \(200\,\text{m}\). The total displacement of the body during the second half-second, fourth half-second and sixth half-second of its motion is (Acceleration due to gravity \(=10\,\text{m s}^{-2}\)):

A body is projected with a velocity of \(15\sqrt3\,\text{m s}^{-1}\) at an angle of \(60^\circ\) with the horizontal and another body is projected simultaneously from the same point in the same vertical plane with a velocity of \(40\,\text{m s}^{-1}\) at an angle of \(30^\circ\) with the horizontal. The time at which the velocity vectors of the two bodies will be in the same direction is:

Acceleration varies as $a = 6t$. Starting from rest, the velocity of the particle after $t = 2\text{ s}$ is:

The three graphs represent acceleration Vs time for objects that have positive velocity at time \( t_1 \). Which graphs show the objects that move with increasing velocity for the entire time interval between \( t_1 \) and \( t_2 \)?

Two objects A and B are projected with same velocity at angles \( \theta \) and \( 90-\theta \) respectively with the horizontal. Then the ratio of maximum heights they reached \( \frac{H_A}{H_B} \) is:

A particle has initial velocity \( 2\hat{i} + 3\hat{j} \) \( ms^{-1} \) and acceleration \( 0.8\hat{i} + 0.6\hat{j} \) \( ms^{-2} \). Its velocity after 5 sec is (in \( ms^{-1} \)):

A velocity-time graph is drawn for two different objects. They make \( 30^{\circ} \) and \( 45^{\circ} \) with the time axis. Then the ratio of their accelerations, \( a_1: a_2 \) is

An object is projected with an angle of \( 60^{\circ} \) with horizontal with a velocity V. During the path, when it makes \( 30^{\circ} \) with horizontal, its velocity becomes 10 \( ms^{-1} \), then V is:

Two bodies projected with same velocity at different angles attain same range. If the time of flights of the bodies are \( T_{1} \) and \( T_{2} \) respectively, then \( \frac{T_{1}}{T_{2}} \) is:

A particle initially at rest starts moving from origin along X - axis with velocity 'V' that varies as $V = 2\sqrt{x}~ms^{-1}$. The acceleration of the particle in $ms^{-2}$ is:

Cars $X$ and $Y$ begin the race simultaneously with velocities $8\text{ ms}^{-1}$ and $4\text{ ms}^{-1}$, moving in a straight line with uniform accelerations $2\text{ ms}^{-2}$ and $4\text{ ms}^{-2}$ respectively. If they reach final point at the same instant, then the length of the path is

A projectile is thrown into space so that it attains a maximum possible range of $200\text{ m}$. Taking the point of projection as origin, the coordinates of the point where the velocity of projectile is minimum is

A projectile is launched from the ground with an initial velocity $v$ at an angle $\theta$ to the horizontal. If its horizontal range is equal to its maximum height, then the value of $\tan \theta$ is:

A force F = 6t acts on a body of mass 2 kg initially at rest. Find velocity at t = 2 s.

The velocity-time graph of a particle is given by v = 4t. The acceleration is:

Escape velocity on a planet is \(10\ \text{km/s}\). If the radius remains same but the mass becomes \(4\) times, the new escape velocity is:

Vectors of magnitude \(3\) and \(4\) are perpendicular. Resultant?

A projectile is projected with speed \(20\ \text{m/s}\) at an angle of \(30^\circ\). The range is \((g=10\ \text{m/s}^2)\):

A car moving at \(20\ \text{m/s}\) comes to rest with a uniform retardation of \(5\ \text{m/s}^2\). The stopping distance is:

A body starts from rest and accelerates uniformly at \(2\ \text{m/s}^2\). The distance covered in \(5\ \text{s}\) is:

The velocity-time graph of a particle is given by \(v=4t\). The acceleration is:

A particle moves such that its velocity-time graph is a straight line from \(0\ \text{m/s}\) at \(t=0\) to \(20\ \text{m/s}\) at \(t=10\ \text{s}\). The displacement in \(10\ \text{s}\) is:

The coordinates of a particle moving in x-y plane at any instant of time \(t\) is \(x = 4t^2\); \(y = 3t^2\). The speed of the particle at that instant is:

A biker travels \(\frac{1}{3}\) of the distance \(L\) with speed \(v_1\) and \(\frac{2}{3}\) of the distance with speed \(v_2\). Then the average speed is