Question:medium

A uniform wire of length \(l\) of weight \(w\) is suspended from the roof with a weight \(W\) at the other end. The stress in the wire at \( \frac{l}{3} \) distance from the top is} \[ \left(\frac{W}{A} + \frac{2}{\gamma}\frac{w}{A}\right) \] where \(A\) is the cross sectional area of the wire. The value of \(\gamma\) is ____.}

Updated On: Apr 10, 2026
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Correct Answer: 3

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