Question

A uniform thin circular disc of mass \(M\) and radius \(R\) is shown in the figure. The moment of inertia of the shaded region about the diameter AB of the disc is:

• A. \(\frac{7MR^2}{16}\)
• B. \(\frac{7MR^2}{64}\)
• C. \(\frac{7MR^2}{32}\)
• D. \(\frac{MR^2}{16}\)

Hint:

Whenever a portion is removed from a body, \[ I_{\text{remaining}} = I_{\text{original}} - I_{\text{removed}}. \] Also remember: \[ I_{\text{diameter of disc}} = \frac{MR^2}{4}. \]

Answer 1

The Correct Option is B