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A thin uniform wire of mass 'm' and linear density '$\rho$' is bent in the form of a circular ring. The moment of inertia of the ring about a tangent parallel to its diameter is

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The Parallel Axis Theorem is crucial for finding the moment of inertia about any axis, given the moment of inertia about a parallel axis through the center of mass. Remember the formula: $I = I_{cm} + Md^2$.

Updated On: Mar 30, 2026

$ \frac{3m^3}{8\pi^2\rho^2} $
$ \frac{8m^3}{3\pi^2\rho^2} $
$ \frac{8\pi^2m^3}{3\rho^2} $
$ \frac{3\pi^2m^3}{8\rho^2} $

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The Correct Option is A

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A thin uniform wire of mass 'm' and linear density '\(\rho\)' is bent in the form of a circular ring. The moment of inertia of the ring about a tangent parallel to its diameter is

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The Correct Option is A

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