Question:hard

A survey on population growth was conducted in town A. It revealed that the population of the town was 5.477 lakh. In one year, there is an increase in men (aged above 18 years) population by 8%, increase in population of women (aged above 18 years) by 12.5% and increase in the population of children (boy or a girl aged less or equal to 18 years) by 12%. If the population of town A, after one year was found to be 6.0466 lakh and number of children was found to be 91,840, then what was the population of men in the town before survey?

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First isolate the children's original count from the 12% growth, then set up two equations in men and women and eliminate one variable.
Updated On: Jul 20, 2026
  • 246500
  • 256400
  • 268400
  • 272600
  • 289450
Show Solution

The Correct Option is A

Solution and Explanation

Start the same way: children before the survey = $91840 / 1.12 = 82000$, so men plus women before the survey totalled $547700 - 82000 = 465700$.
After growth, men plus women together equal $604660 - 91840 = 512820$.
This time eliminate men instead of women. From $M + W = 465700$, write $M = 465700 - W$ and substitute into $1.08M + 1.125W = 512820$:
$1.08(465700 - W) + 1.125W = 512820$
$502956 - 1.08W + 1.125W = 512820$
$0.045W = 9864$
$W = 219200$
So men $= 465700 - 219200 = 246500$, confirming the men's population before the survey was 246500.
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