Question:medium

A stone of mass \(10\,\text{g}\) is attached to a string of length \(80\,\text{cm}\) and is rotated in a horizontal circle at a height of \(h\) from the ground with a centripetal acceleration of \(125\,\text{m s}^{-2}\). At a moment the string breaks and the stone strikes the ground at a horizontal distance of \(10\,\text{m}\). Then the value of \(h\) is \[ (\text{Acceleration due to gravity}=10\,\text{m s}^{-2}) \]

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For a body projected horizontally, \[ \boxed{x=vt,\qquad h=\frac12gt^2.} \] First find the horizontal speed from centripetal motion and then use projectile motion equations.
Updated On: Jul 18, 2026
  • \(10\,\text{m}\)
  • \(5\,\text{m}\)
  • \(15\,\text{m}\)
  • \(20\,\text{m}\)
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The Correct Option is B

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