A sportsman runs around a circular track of radius $ r $ such that he traverses the path ABAB. The distance travelled and displacement, respectively, are:

Displacement is defined as the shortest distance between the starting and ending positions. Given that the athlete completes circuits on a circular track and returns to their origin (point A), the displacement is the diameter of the circle. Consequently: \[ \text{Displacement} = 2r \] The distance covered represents the total length of the athlete's path, comprising three full circuits of the track. Hence, the total distance is: \[ \text{Distance} = 2\pi r + \pi r = 3\pi r \] Therefore, the correct response is: \[ 3\pi r, 2r \]

A body of mass $100 \;g$ is moving in a circular path of radius $2\; m$ on a vertical plane as shown in the figure. The velocity of the body at point A is $10 m/s.$ The ratio of its kinetic energies at point B and C is: (Take acceleration due to gravity as $10 m/s^2$)
