Question:medium

A solid sphere of mass 2 kg and radius 0.5 m is rolling without slipping on a horizontal surface. The ratio of the rotational and translational kinetic energies of the sphere is

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For any object rolling without slipping, the ratio of its rotational kinetic energy to its translational kinetic energy is a constant that depends only on its shape (through the moment of inertia formula). It can be written as $KE_R/KE_T = I/(mr^2)$, where $I=kmr^2$, so the ratio is just $k$. For a solid sphere, $k=2/5$.

Updated On: Mar 30, 2026

3:5
2:5
4:5
7:5

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The Correct Option is B

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