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A solid sphere of mass 2 kg and radius 0.5 m is rolling without slipping on a horizontal surface. The ratio of the rotational and translational kinetic energies of the sphere is
A solid sphere of mass 2 kg and radius 0.5 m is rolling without slipping on a horizontal surface. The ratio of the rotational and translational kinetic energies of the sphere is
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For any object rolling without slipping, the ratio of its rotational kinetic energy to its translational kinetic energy is a constant that depends only on its shape (through the moment of inertia formula). It can be written as $KE_R/KE_T = I/(mr^2)$, where $I=kmr^2$, so the ratio is just $k$. For a solid sphere, $k=2/5$.
Updated On: Mar 30, 2026
- 3:5
- 2:5
- 4:5
- 7:5
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The Correct Option is B
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