Question:medium

A soap bubble of radius \(r = 1\,\text{mm}\) is rising in a liquid of density \( \rho = 2000\,\text{kg/m}^3 \). At the instant the bubble is rising upward with constant velocity \(v = \tfrac{1}{2}\,\text{cm/s}\). Find the coefficient of viscosity \( (\eta) \).

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For terminal velocity problems using Stokes' law: \[ v = \frac{2r^2(\rho-\rho_f)g}{9\eta} \] For bubbles, density of gas is negligible, so \( \rho_f \) dominates.
Updated On: Apr 2, 2026
  • \( \dfrac{2}{9}\ \text{N·s/m}^2 \)
  • \( \dfrac{4}{9}\ \text{N·s/m}^2 \)
  • \( \dfrac{2}{3}\ \text{N·s/m}^2 \)
  • \( \dfrac{8}{9}\ \text{N·s/m}^2 \)
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The Correct Option is A

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