Question:medium

A siren emitting sound of frequency \(800\,Hz\) is going away from a static listener with a speed of \(30\,m/s\). Frequency of sound heard by the listener is \((\text{velocity of sound in air}=340\,m/s)\)

Show Hint

When source moves away from listener, apparent frequency decreases and denominator becomes \(v+v_s\).
  • \(286.5\,Hz\)
  • \(418.2\,Hz\)
  • \(733.3\,Hz\)
  • \(644.5\,Hz\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
This problem involves the Doppler effect for sound waves. The apparent frequency heard by a listener changes when there is relative motion between the source of the sound and the listener. When the source moves away from the listener, the observed frequency decreases.
Step 2: Key Formula or Approach:
The general formula for the Doppler effect is: \[ f' = f \left( \frac{v \pm v_L}{v \mp v_S} \right) \] where: - $f'$ is the observed frequency. - $f$ is the source frequency. - $v$ is the speed of sound. - $v_L$ is the speed of the listener. - $v_S$ is the speed of the source. The sign convention is: use the top sign for motion towards each other and the bottom sign for motion away from each other. In this case: - The listener is static, so $v_L = 0$. - The source is moving away from the listener, so we use the bottom sign in the denominator (+).
Step 3: Detailed Explanation:
Given: - Source frequency, $f = 800$ Hz. - Speed of sound, $v = 340$ m/s. - Speed of the source, $v_S = 30$ m/s. - Speed of the listener, $v_L = 0$ m/s. The formula for a source moving away from a stationary listener is: \[ f' = f \left( \frac{v}{v + v_S} \right) \] Substitute the given values: \[ f' = 800 \left( \frac{340}{340 + 30} \right) \] \[ f' = 800 \left( \frac{340}{370} \right) \] \[ f' = 800 \times \frac{34}{37} \] \[ f' = \frac{27200}{37} \approx 735.13 \text{ Hz} \] Looking at the options, 733.3 Hz is the closest value. The slight difference might be due to rounding in the problem's intended answer or values. Let's re-check the calculation. $27200 / 37 = 735.135...$. Option (C) 733.3 Hz is close. Let's assume there might be a typo in the options or the question values. However, based on standard calculation, it is the most plausible answer. Let's calculate $800 \times (340/370) = 800 \times 0.9189... = 735.1...$ Hz. The value 733.3 Hz would be obtained if $f' = 800 \times (330 / 360) = 800 \times (11/12) \approx 733.3$. This suggests the intended values might have been $v=330$ and $v_S=30$. Using the given values, 735.13 Hz is the correct answer, and 733.3 Hz is the closest option. Step 4: Final Answer:
The calculated frequency is approximately 735.1 Hz. The closest option is 733.3 Hz. Therefore, option (C) is the correct answer.
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