Step 1: Understanding the Concept:
The time period of a pendulum is \( T = 2\pi\sqrt{L/g_{\text{eff}}} \). For \( T \) to decrease, the effective acceleration \( g_{\text{eff}} \) must increase.
Key Formula or Approach:
The effective acceleration is the vector sum of gravitational and electric accelerations:
\[ \vec{g}_{\text{eff}} = \vec{g} + \frac{q\vec{E}}{m} \]
Step 2: Detailed Explanation:
1. Gravity: Points in \( -\hat{z} \).
2. Condition: We need \( |\vec{g}_{\text{eff}}| > g \). This happens if the electric force has a downward component (along \( -\hat{z} \)).
3. Analyze Options:
$\bullet$ (B) \( q>0, \hat{n} = -\hat{z} \): Force is downward. \( g_{\text{eff}} = g + qE/m \). Correct (T decreases).
$\bullet$ (C) \( q<0, \hat{n} = \hat{z} \): Force is \( q\vec{E} = (-|q|)(|E|\hat{z}) \), which is downward. Correct (T decreases).
$\bullet$ (D) \( \hat{n} \cdot \hat{z} = -1/\sqrt{2} \): The unit vector has a downward component. For \( q>0 \), force has a downward component. Correct (T decreases).
$\bullet$ (A) \( q>0, \hat{n} = \hat{z} \): Force is upward (along \( +\hat{z} \)). \( g_{\text{eff}} = g - qE/m \), which is less than \( g \). This makes \( T \) increase. Therefore, this statement is incorrect.
Step 3: Final Answer:
Statement (A) is the incorrect one.