Question

In a series circuit, if the resistance is doubled, what happens to the current?

• A. It doubles
• B. It halves
• C. It remains the same
• D. It becomes zero

Hint:

Current is inversely proportional to resistance in a series circuit with constant voltage.

Answer 1

The Correct Option is B

Ohm's Law for a series circuit is \(I = \frac{V}{R}\), with \(V\) representing voltage and \(R\) representing resistance. When resistance is doubled (\(R \to 2R\)) while voltage is held constant, the new current is calculated as: \[ I_{\text{new}} = \frac{V}{2R} = \frac{1}{2} \cdot \frac{V}{R} = \frac{I}{2} \] Consequently, the current is halved, making option (2) the correct choice.