In a series circuit, if the resistance is doubled, what happens to the current?

Question

A sequence is defined as follows: \( a_1 = 1, a_2 = 2 \), and \( a_n = a_{n-1} + a_{n-2} \) for \( n \geq 3 \). What is the 6th term of the sequence?

Answer 1

Ohm's Law for a series circuit is \(I = \frac{V}{R}\), with \(V\) representing voltage and \(R\) representing resistance. When resistance is doubled (\(R \to 2R\)) while voltage is held constant, the new current is calculated as: \[ I_{\text{new}} = \frac{V}{2R} = \frac{1}{2} \cdot \frac{V}{R} = \frac{I}{2} \] Consequently, the current is halved, making option (2) the correct choice.

In a series circuit, if the resistance is doubled, what happens to the current?

Show Hint

The Correct Option is B

Solution and Explanation

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