Question:medium

A simple pendulum has time period \(T_1\). The point of suspension is now moved upward according to the relation \(y = kt^2\) where \(k = 1\) ms\(^{-2}\). The time period now becomes \(T_2\). The ratio \(\frac{T_1^2}{T_2^2}\) is \((g = 10\) m/s\(^2)\)

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Upward acceleration of support increases effective g, decreases time period.
Updated On: Apr 23, 2026
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The Correct Option is A

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