Question:medium

A rod of length \(L\) is composed of two equal parts: half wood (mass \(m_w\)) and half brass (mass \(m_b\)). The moment of inertia about an axis through its centre and perpendicular to the rod is:

Show Hint

If rod is symmetric about centre, use \( \frac{1}{12}ML^2 \) directly.
Updated On: Apr 16, 2026
  • \( \frac{(m_w + m_b)L^2}{6} \)
  • \( \frac{(m_w + m_b)L^2}{2} \)
  • \( \frac{(m_w + m_b)L^2}{12} \)
  • \( \frac{(m_w + m_b)L^2}{3} \)
Show Solution

The Correct Option is C

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