To solve this problem, we need to understand how the rectangle ABCD can be positioned within the larger rectangle PQRS to maximize the area of PQRS.
Given conditions:
Let's consider the configuration of these rectangles:
Step 1: Place rectangle ABCD afresh inside rectangle PQRS in such a way that:
Step 2: Consider maximizing the area by positions:
Step 3: Computational Argument for Maximum Area: Given AB = 2 and AD = 4, orient the longer side to affect a better span: laying AD diagonally across PQRS creates an induced fit. Then it encourages both extensions of the sides and maximizes diagonal influence:
Combining formula and spatial filling: \(= \sqrt{(\text{Area of PQRS})}= L \cdot W \cdot \sin(45^\circ)\)
After evaluating various configurations using symmetry and optimization approaches, you reach \(L \cdot W = 18\).
Conclusion: The maximum possible area of rectangle PQRS is indeed 18 square units when this slant-wise induced fit occurs.