A proton and an alpha particle have equal momentum. The ratio of their kinetic energies (\(E_p /E_\alpha\)) and de Broglie wavelengths associated with them (\(\lambda_p /\lambda_\alpha\)) respectively are :
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Since the de Broglie wavelength depends solely on momentum (\(\lambda = \frac{h}{p}\)), any two particles with equal momentum will always have identical de Broglie wavelengths, meaning their wavelength ratio must be 1. This helps you eliminate options immediately.