List of top Physics Questions on de broglie hypothesis asked in CBSE CLASS XII

The de Broglie wavelength associated with an electron moving with energy 5 eV is:
The kinetic energy of an alpha particle is four times the kinetic energy of a proton. The ratio \( \left( \frac{\lambda_\alpha}{\lambda_p} \right) \) of de Broglie wavelengths associated with them will be:
The wavelength of a photon is equal to the wavelength associated with an electron. Both will have the same value of:
Let \( \lambda_e, \lambda_p, \lambda_d \) be the wavelengths associated with an electron, a proton, and a deuteron, all moving with the same speed. Then the correct relation between them is: