Question

A perpendicular is drawn from the point \( P(2,4,-1) \) to the line \( \frac{x+5}{1}=\frac{y+3}{4}=\frac{z-6}{-9} \). The equation of the perpendicular from \( P \) to the given line is

• A. $\frac{x-2}{6}=\frac{y-4}{3}=\frac{z+1}{2}$
• B. $\frac{x+2}{6}=\frac{y-4}{3}=\frac{z+1}{2}$
• C. $\frac{x+2}{-6}=\frac{y-4}{3}=\frac{z+1}{2}$
• D. $\frac{x+2}{6}=\frac{y+4}{3}=\frac{z+1}{2}$

Hint:

For perpendicular lines in 3D, use dot product = 0 condition.

Answer 1

The Correct Option is A