The area of a triangle with base 12 cm and height 5 cm is?

Question

If the distances of the point \( (1,2,a) \) from the line \[ \frac{x-1}{1}=\frac{y}{2}=\frac{z-1}{1} \] along the lines \[ L_1:\ \frac{x-1}{3}=\frac{y-2}{4}=\frac{z-a}{b} \quad \text{and} \quad L_2:\ \frac{x-1}{1}=\frac{y-2}{4}=\frac{z-a}{c} \] are equal, then \( a+b+c \) is equal to:

Answer 1

The area of a triangle is calculated using the formula: \[ \text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} \] With a Base of 12 cm and a Height of 5 cm, substituting these values yields: \[ \text{Area} = \frac{1}{2} \times 12 \times 5 = 30 \, \text{cm}^2 \] The triangle's area is 30 cm\(^2\). This corresponds to option (1).

The area of a triangle with base 12 cm and height 5 cm is?

Show Hint

The Correct Option is A

Solution and Explanation

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