Question:medium

A particle moves on a circular path of radius 1 m. Find its displacement when it moves from \( A \rightarrow B \rightarrow A \). Also, its distance are it moves from \( A \rightarrow B \rightarrow A \).

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When a particle moves along a circular path and returns to its starting point, the distance is the length of the arc while the displacement is the straight-line distance between the two points.
Updated On: Mar 29, 2026
  • Distance = 2 m, Displacement = \( 4\pi \) m
  • Distance = 2 m, Displacement = \( 5\pi \) m
  • Distance = \( 4\pi \) m, Displacement = 2 m
  • Distance = 2 m, Displacement = 2 m
Show Solution

The Correct Option is D

Solution and Explanation

- The particle traverses a circular path of radius \( r = 1 \, \text{m} \). - The total path length from \( A \) to \( B \) and back to \( A \) is calculated. This involves covering half the circle in each direction. The total distance is the perimeter of the semicircle: \[ \text{Distance} = \pi r = \pi \times 1 = \pi \, \text{m}. \] - Displacement is defined as the shortest straight-line distance between the initial and final positions. Since the particle moves from \( A \) to \( B \) and then directly back to \( A \) across the circle's diameter, the displacement is \( 2 \, \text{m} \). Therefore, option (4) is correct, stating a distance of \( 2 \, \text{m} \) and a displacement of \( 2 \, \text{m} \).
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