Question:medium

A particle is travelling 4 times as fast as an electron. Assuming the ratio of de-Broglie wavelength of a particle to that of electron is 2 : 1, the mass of the particle is :

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De-Broglie wavelength is inversely proportional to momentum ($p=mv$). If wavelength is larger, momentum must be smaller.
Updated On: Feb 10, 2026
  • 8 times the mass of e⁻
  • 1/16 times the mass of e⁻
  • 16 times the mass of e⁻
  • 1/8 times the mass of e⁻
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The Correct Option is D

Solution and Explanation

Given:

Velocity of particle = 4 × velocity of electron
vp = 4ve

Ratio of de-Broglie wavelengths:
λp : λe = 2 : 1


Step 1: Write de-Broglie wavelength formula

λ = h / mv


Step 2: Take ratio of wavelengths

λp / λe = (h / mpvp) / (h / meve)

λp / λe = (meve) / (mpvp)

Given λp / λe = 2

(meve) / (mpvp) = 2


Step 3: Substitute vp = 4ve

(meve) / (mp · 4ve) = 2

me / (4mp) = 2


Step 4: Solve for mp

me = 8mp

mp = me / 8


Final Answer:

The mass of the particle is,
1/8 times the mass of the electron

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