This problem concerns a nucleus that breaks into two smaller nuclei. The mass ratio of these resulting nuclei is 2:1. The objective is to determine the ratio of their speeds post-disintegration, utilizing the principle of conservation of momentum.
Concept: Conservation of Momentum
The law of conservation of momentum dictates that the total momentum of an isolated system remains constant. For a system where no external forces are present, the initial momentum equals the final momentum. In this scenario, the nucleus is initially stationary, thus possessing zero initial momentum.
Solution Steps
- System Definition: The initial momentum of the nucleus is zero as it is at rest.
- Assign Variables:
- Let the masses of the two daughter nuclei be \( m_1 \) and \( m_2 \). Given the mass ratio of 2:1, we can set \( m_1 = 2m \) and \( m_2 = m \).
- Let their respective velocities be \( v_1 \) and \( v_2 \).
- Apply Momentum Conservation: The initial momentum (0) must equal the final momentum. Since the nuclei move in opposite directions, one velocity will be negative relative to the other. Thus: \( 0 = m_1 \cdot v_1 + m_2 \cdot (-v_2) \). Substituting the masses: \( 0 = (2m) \cdot v_1 - m \cdot v_2 \). This rearranges to \( 2m \cdot v_1 = m \cdot v_2 \).
- Equation Simplification: Divide both sides by \( m \) to yield \( 2v_1 = v_2 \).
- Speed Ratio Determination: From \( 2v_1 = v_2 \), we can express the ratio of speeds as \( v_1 : v_2 = 1 : 2 \).
Outcome
Consequently, following disintegration, the two smaller nuclei will move in opposite directions. Their speeds will be in the ratio of 1:2.
The precise answer is: "In opposite directions with speed in the ratio of 1:2 respectively".