This problem concerns a nucleus that breaks into two smaller nuclei. The mass ratio of these resulting nuclei is 2:1. The objective is to determine the ratio of their speeds post-disintegration, utilizing the principle of conservation of momentum.
The law of conservation of momentum dictates that the total momentum of an isolated system remains constant. For a system where no external forces are present, the initial momentum equals the final momentum. In this scenario, the nucleus is initially stationary, thus possessing zero initial momentum.
Consequently, following disintegration, the two smaller nuclei will move in opposite directions. Their speeds will be in the ratio of 1:2.
The precise answer is: "In opposite directions with speed in the ratio of 1:2 respectively".
The electric potential at the surface of an atomic nucleus \( (z = 50) \) of radius \( 9 \times 10^{-13} \) cm is \(\_\_\_\_\_\_\_ \)\(\times 10^{6} V\).
In a nuclear fission reaction of an isotope of mass \( M \), three similar daughter nuclei of the same mass are formed. The speed of a daughter nuclei in terms of mass defect \( \Delta M \) will be: