Question:medium

A long solenoid of length $L$ has a mean diameter $D$. It has $n$ layers of winding of $N$ turns each. If it carries a current $i$, the magnetic field at its centre will be

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Magnetic field inside a long solenoid depends only on the number of turns per unit length and the current.
Updated On: May 3, 2026
  • proportional to $D$
  • inversely proportional to $D$
  • independent of $D$
  • proportional to $L$
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The Correct Option is C

Solution and Explanation

To determine the magnetic field at the center of a solenoid, we must consider the formula for the magnetic field inside a long solenoid:

\(B = \mu_0 \cdot n_{\text{total}}\cdot i\)

where:

  • \(B\) is the magnetic field.
  • \(\mu_0\) is the permeability of free space.
  • \(n_{\text{total}}\) is the total number of turns per unit length of the solenoid.
  • \(i\) is the current flowing through the solenoid.

For a solenoid with \(N\) turns and length \(L\), the number of turns per unit length is given by:

\(n_{\text{total}} = \frac{N \cdot n}{L}\)

Substituting this into the magnetic field formula:

\(B = \mu_0 \cdot \frac{N \cdot n}{L} \cdot i\)

From this expression, observe that:

  • The magnetic field \(B\) is dependent on \(N\)\(n\)\(L\), and \(i\).
  • Importantly, \(B\) is independent of the diameter \(D\) of the solenoid.

This leads to the conclusion that the magnetic field at the center of a long solenoid is:

Independent of \(D\).

Among the given options, the correct answer is independent of \(D\), confirming that the diameter of the solenoid does not influence the magnetic field at its center.

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