Question:medium

Strength of magnetic field produced by a current carrying solenoid DOES NOT depend upon:

Updated On: Jan 13, 2026
  • number of turns in the solenoid
  • direction of the current flowing through it
  • radius of solenoid
  • material of core of the solenoid
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Solenoid Magnetic Field Strength Factors:
A solenoid's magnetic field strength is influenced by the current (\(I\)), the number of turns (\(N\)), and the solenoid's length (\(L\)). The internal magnetic field is calculated using the formula:
\[B = \mu_0 \frac{N}{L} I\]Where:
- \( B \) represents the magnetic field strength.
- \( \mu_0 \) is the permeability of free space.
- \( N \) is the total number of turns in the solenoid.
- \( L \) is the solenoid's length.
- \( I \) is the current magnitude flowing through the solenoid.


Step 2: Influencing Factors on Magnetic Field Strength:
- The magnetic field strength is directly proportional to the current (\( I \)) and the number of turns (\( N \)).
- It is inversely proportional to the solenoid's length (\( L \)).
- The core material of the solenoid also impacts field strength. However, the direction of the current does not affect the field's magnitude.


Step 3: Option Analysis:
The magnetic field generated by a solenoid is contingent upon variables like current (\( I \)), turns (\( N \)), and length (\( L \)). Crucially, the direction of the current does not influence the field's strength. While current direction dictates the field's direction, it has no bearing on its magnitude.


Step 4: Conclusion:
The correct factor is: direction of the current flowing through it. The magnitude of the magnetic field within a solenoid is independent of the current's direction; it depends on the current's magnitude, the number of turns, and the solenoid's length.

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