To determine the magnetic field inside a long cylindrical conductor carrying current, we consider Ampère's Law, which relates the magnetic field (\(\mathbf{B}\)) around a closed loop to the current passing through the loop.
The formula for Ampère's Law is:
\(\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I_{\text{enc}}\)
Where:
We consider a loop of radius \(r\) inside the conductor. The current density is uniform, so the current enclosed by our loop is proportional to the area of the loop:
\(I_{\text{enc}} = J \pi r^2\)
Where \(J\) is the current density. The total current \(I\) is given by:
\(I = J \pi R^2\)
Where \(R\) is the radius of the conductor.
Using Ampère's Law and recognizing that symmetry allows us to assume \(\mathbf{B}\) is constant in magnitude at a radial distance from the conductor's axis:
\(B \cdot 2 \pi r = \mu_0 J \pi r^2\)
Simplifying for \(B\), we have:
\(B = \frac{\mu_0 J r}{2}\)
Since \(J = \frac{I}{\pi R^2}\), substituting this into the equation for \(B\) gives:
\(B = \frac{\mu_0 I r}{2 \pi R^2}\)
This equation shows that the magnetic field \(B\) varies linearly with \(r\), meaning it is minimum (zero) at the axis (\(r = 0\)) and increases as one moves towards the surface. Therefore, the magnetic field is minimum at the axis.
Given the options, this analysis matches with option D: "minimum at the axis of the conductor."