Question:medium

A liquid of density \(800\,\text{kg m}^{-3}\) rises \(4\,\text{cm}\) in a capillary tube of inner radius \(0.2\,\text{mm}\). The capillary tube is dipped vertically in the liquid and the angle of contact between the capillary tube and the liquid is \(0^\circ\). The excess pressure inside the spherical drop of diameter \(2\,\text{cm}\) of the same liquid is \[ (\text{Acceleration due to gravity}=10\,\text{m s}^{-2}) \]

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Remember, \[ \boxed{ h=\frac{2T\cos\theta}{\rho gr} } \] for capillary rise, and \[ \boxed{ \Delta P=\frac{2T}{R} } \] for a liquid drop.
Updated On: Jul 18, 2026
  • \(9.6\,\text{N m}^{-2}\)
  • \(12.8\,\text{N m}^{-2}\)
  • \(6.4\,\text{N m}^{-2}\)
  • \(3.2\,\text{N m}^{-2}\)
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The Correct Option is C

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