Question:medium

A horizontal force of 10 N is applied on a block of mass 1.5 kg which is initially at rest on a rough horizontal surface. The work done by the applied force in a time of 6 s from the beginning of the motion is (Acceleration due to gravity = 10 ms\(^{-2}\); the coefficient of kinetic friction between the block and the surface is 0.2)

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Be careful to distinguish between the work done by the *applied force* and the *net work* done. Net work would be calculated using the net force (\(W_{net} = F_{net} \times s = 7 \times 84 = 588\) J), which equals the change in kinetic energy. The question specifically asks for the work done by the applied force.

Updated On: Mar 30, 2026

588 J
360 J
840 J
420 J

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The Correct Option is C

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