The person has no toffees remaining after distributing to the fifth student.
Each student receives one more than half the number of toffees available at that point.
For this problem, working backward is the most efficient approach. If the person had not given an additional toffee, they would have retained that single toffee.
This implies the person had \(2\) toffees at that stage. In the preceding stage (the 4th stage), they must have had \((2+1)×2\), which equals \(6\) toffees. In the 3rd stage, they should have had \((6+1)×2\), totaling \(14\) toffees.
In the 2nd stage, they should have had \((14+1)×2\), resulting in \(30\) toffees.
In the 1st stage, they should have had \((30+1)×2\), which amounts to \(62\) toffees.
Therefore, the initial number of toffees was \(62\).
A positive integer $m$ is increased by 20% and the resulting number is 1080. Then the integer $m$ is
If one-fourth of a number exceeds 20% of the number by 10, then the number is
A software company lays off 40% of its employees. Among the laid-off employees, 20% are developers. The percentage of laid-off developers from the total employees of the company is