Question:medium

A gas expands from volume \(V\) to \(2V\) at constant pressure \(P\). What is the work done by the gas?

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In an isobaric process, the area under the \(P\)-\(V\) graph (a rectangle) gives the work: \(W = P \Delta V\).
Updated On: Jan 13, 2026
  • \(PV\)
  • \(2PV\)
  • \(\frac{PV}{2}\)
  • Zero
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The Correct Option is A

Solution and Explanation

Step 1: Apply the formula for work done in an isobaric process. Work done during isobaric expansion of a gas is calculated as: \[ W = P(V_2 - V_1) \] Provided values: - Initial volume: \(V_1 = V\) - Final volume: \(V_2 = 2V\) - Constant pressure: \(P = P\) Substituting these values into the formula: \[ W = P(2V - V) = P \cdot V \] Step 2: State the final result. The gas performs \(PV\) amount of work. Answer: The correct answer is option (1), which is \(PV\).
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