The problem involves the concept of radioactive decay, characterized by its half-life, which is the time required for a quantity of a radioactive substance to reduce to half its initial amount. Given:
Initial intensity: 64 times the safe level.
Half-life \( T_{1/2} = 2.5 \) hours (2 hours 30 minutes).
Let \( I_0 \) be the initial intensity, and \( I_s \) the safe level. After time \( t \), the intensity is \( I(t) = I_0 \times (1/2)^{t/T_{1/2}} \).
We want \( I(t) = I_s \).
\[ \frac{I_0}{I_s} \times (1/2)^{t/T_{1/2}} = 1 \]
\[ 64 \times (1/2)^{t/2.5} = 1 \]
Solve for \( t \):
\[ (1/2)^{t/2.5} = 1/64 \]
\[ 2^{t/2.5} = 64 \]
\[ 2^{t/2.5} = 2^6 \]
Equating exponents,
\[ \frac{t}{2.5} = 6 \]
\[ t = 6 \times 2.5 = 15 \text{ hours} \]
Thus, the minimum time required is 15 hours. This result fits within the given range, confirming its correctness.