A bag contains 5 red balls, 7 green balls, and 8 blue balls. One ball is drawn at random. What is the probability that the ball is either red or green?
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Remember: To calculate probability, divide the number of favorable outcomes by the total number of outcomes.
Given: The total number of balls in the bag is \(5 \text{ red balls} + 7 \text{ green balls} + 8 \text{ blue balls} = 20 \text{ balls}\).
Step 1: Calculate favorable outcomes The favorable outcomes are drawing a red or a green ball. The total number of favorable outcomes is \(5 \text{ red balls} + 7 \text{ green balls} = 12 \text{ favorable outcomes}\).
Step 2: Calculate the probability The probability of drawing a red or green ball is \(P(\text{red or green}) = \frac{12}{20} = \frac{3}{5}\).
Answer: The correct answer is option (3): \( \frac{12}{20} \).