Question

A die is thrown once. What is the probability of getting a number greater than 4?

• A. \frac{1}{2}
• B. \frac{1}{3}
• C. \frac{1}{6}
• D. \frac{2}{3}

Hint:

Probability of an event = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}.

Answer 1

The Correct Option is B

A standard die exhibits faces numbered 1 through 6.
The numbers exceeding 4 are 5 and 6, constituting 2 favorable outcomes.
The total number of possible outcomes is 6.
The probability is calculated as \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{2}{6}, which simplifies to \frac{1}{3}.