Question:medium
A convex lens of radii of curvature 6 cm and 12 cm is immersed in a liquid of refractive index 1.3. If the refractive index of the material of the lens is 1.5, then the focal length of the lens when immersed in the liquid is
A convex lens of radii of curvature 6 cm and 12 cm is immersed in a liquid of refractive index 1.3. If the refractive index of the material of the lens is 1.5, then the focal length of the lens when immersed in the liquid is
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The Lens Maker's formula is $\frac{1}{f} = (n_{rel}-1)(\frac{1}{R_1}-\frac{1}{R_2})$, where $n_{rel}$ is the refractive index of the lens relative to the surrounding medium ($n_{rel} = n_{lens}/n_{medium}$). Remember the sign convention for radii of curvature (light travels left to right, centers of curvature to the right are positive, to the left are negative).
Updated On: Mar 30, 2026
- 39 cm
- 13 cm
- 26 cm
- 52 cm
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The Correct Option is C
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