Question:medium

A charged particle of mass 0.003 g is held stationary in space by placing it in a downward direction of electric field of \(6 \times 10^4\) N/C. Then the magnitude of the charge is

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For stationary particle, \(qE = mg\), direction of E determines sign.
Updated On: Apr 7, 2026
  • \(5 \times 10^{-4}\) C
  • \(5 \times 10^{-10}\) C
  • \(-18 \times 10^{-6}\) C
  • \(-5 \times 10^{-9}\) C
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The Correct Option is B

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