Question

A charge of \(2 \times 10^{-2} \, C\) moves at 30 rev/s in a circle of diameter 80 cm. The current linked with the circuit is :

• A. 0.02 A
• B. 20 A
• C. 0.60 A
• D. 60 A

Hint:

Current in circular motion = charge × frequency.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
Electric current is defined as the rate of flow of charge. For a charge moving in a closed loop, the effective current is the product of the charge and the frequency of revolution.
: Key Formula or Approach:
\[ I = \frac{q}{T} = q \cdot f \]
where \( f \) is the frequency in rev/s (Hz).
Step 2: Detailed Explanation:
Given:
Charge \( q = 2 \times 10^{-2} \text{ C} \).
Frequency \( f = 30 \text{ rev/s} \).
(Diameter is given but not needed for basic current calculation).
Calculating current:
\[ I = q \times f \]
\[ I = (2 \times 10^{-2} \text{ C}) \times (30 \text{ s}^{-1}) \]
\[ I = 60 \times 10^{-2} \text{ A} \]
\[ I = 0.60 \text{ A} \]
Step 3: Final Answer:
The current linked with the circuit is 0.60 A.