Question

A carbon resistor of $(47 \pm 4.7) \, k \Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be

• A. Green - Orange- Violet- Gold
• B. Violet - Yellow - Orange - Silver
• C. Yellow - Green - Violet - Gold
• D. Yellow - Violet - Orange - Silver

Answer 1

The Correct Option is D

To determine the color code for a carbon resistor with a resistance of \( (47 \pm 4.7) \, k \Omega \), we need to decode the resistance value into its corresponding color bands.

1. The resistance value given is \( 47 \, k \Omega \). Converting this to ohms, you get \( 47,000 \, \Omega \).
2. The tolerance is \(\pm 10\%\), indicated by Gold or Silver.
3. The color code for a resistor is decoded as:
   • The first two digits represent the significant figures.
   • The third digit is the multiplier.
   • The fourth band represents the tolerance.
4. For the resistance \( 47,000 \, \Omega \):
   • The first digit is 4, represented by Yellow.
   • The second digit is 7, represented by Violet.
   • The multiplier is \( 1,000 = 10^3 \), represented by Orange.
   • The tolerance is \( \pm 10\% \), represented by Silver.

Thus, the complete color code for a resistor of \( (47 \pm 4.7) \, k \Omega \) is Yellow - Violet - Orange - Silver.