The capillary rise formula, \(h = \frac{2T \cos \theta}{\rho g r}\), determines the length of water that ascends in a capillary tube. The formula's variables are defined as follows:
Substituting these values into the formula yields:
\(h = \frac{2 \times 0.07 \times 1}{1000 \times 9.8 \times 0.1 \times 10^{-3}}\)
The calculation results in:
\(h = \frac{0.14}{0.98 \times 10^{-3}} = \frac{0.14 \times 10^3}{0.98}\)
\(h = \frac{140}{0.98} \approx 142.86 \, \text{cm}\)
As the tube is inclined at \(30^\circ\) to the vertical, the actual length of water in the tube is influenced by this angle. The actual length is calculated using the formula: \(\text{Length} = \frac{h}{\sin 30^\circ}\).
Given that \(\sin 30^\circ = \frac{1}{2}\), the actual length is:
\(\text{Length} = \frac{142.86}{\frac{1}{2}} = 2 \times 142.86 = 285.72 \, \text{cm}\)
Among the provided options, the value closest to \(285.72 \, \text{cm}\) is \(\frac{82}{5}\) multiplied by \(10\). Thus, the correct answer is:
\(\frac{82}{5}\)
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity) 
Two soap bubbles of radius 2 cm and 4 cm, respectively, are in contact with each other. The radius of curvature of the common surface, in cm, is _______________.