Question:medium

A cafeteria offers 5 types of sandwiches. Moreover, for each type of sandwich, a customer can choose one of 4 breads and opt for either small or large sized sandwich. Optionally, the customer may also add up to 2 out of 6 available sauces. The number of different ways in which an order can be placed for a sandwich, is:

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When a question says “up to $k$ items” from $n$ options, sum the combinations: \[ \sum_{r=0}^{k} \binom{n}{r}. \] Then multiply by the number of ways for all other independent choices.
Updated On: Jul 4, 2026
  • \(600\)
  • \(840\)
  • \(880\)
  • \(800\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Fixed part first: type, bread and size give \(5 \times 4 \times 2 = 40\) base choices.
Step 2: Count sauce selections by first arranging in order, then dividing out the overcount, since order doesn't actually matter. One sauce: \(6\) ways directly. Two sauces: pick them in order (\(6 \times 5 = 30\) ways), then divide by \(2!\) since each pair is counted twice: \(30/2 = 15\). No sauce: \(1\) way.
Step 3: Total sauce options \(= 1 + 6 + 15 = 22\), so the total orders \(= 40 \times 22 = 880\).
\[ \boxed{880} \]
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