Question

A body projected at certain angle (\(\neq 90^\circ\)) from the ground crosses a point in its path at a time of 2.3 s and from there it reaches the ground after a time of 5.7 s. The maximum height reached by the body is (Acceleration due to gravity = 10 ms\(^{-2}\))

• A. 80 m
• B. 120 m
• C. 40 m
• D. 160 m

Hint:

For any two points on a projectile's trajectory at the same height, the time taken from launch to the first point and the time taken from the second point to landing are equal. The problem implies the body is at the same height at \(t=2.3\)s on the way up and some time \(t'\) on the way down. The time from \(t'\) to landing (5.7s) is equal to the time from launch to \(t=2.3\)s. However, the interpretation used in the solution is more direct.

Answer 1

The Correct Option is A