Question:medium

A body of mass \( m \) rises to a height \( h = \frac{R}{5} \) from the earth's surface, where \( R \) is the earth’s radius. If \( g \) is acceleration due to gravity at the earth’s surface, then the increase in potential energy is:

Show Hint

For large heights comparable to Earth's radius, always use \[ \Delta U = GMm\left(\frac{1}{r_1} - \frac{1}{r_2}\right) \] instead of \( mgh \), which is only valid for small heights.
Updated On: Apr 16, 2026
  • \( mgh \)
  • \( \frac{4}{5} mgh \)
  • \( \frac{5}{6} mgh \)
  • \( \frac{6}{7} mgh \)
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0