\(1: 1\)
\(2: 3\)
\(2:5\)
\(1: 2\)
To solve this problem, we need to find the extension in the spring when the body of mass 200 g moves in a circular path with constant angular speed. We'll use the concepts of circular motion and Hooke's Law for this.
The correct answer is therefore \(\frac{2}{3}\), which matches with the option given as \(2:3\).