Question:medium

A boat which can travel at 10km/hr in still water goes 91km down a river and returns to the starting point in 20 hours. Find the speed of the flow of the river.

Updated On: Jan 13, 2026
  • 3.5kmph
  • 2.5kimph
  • 2kmph
  • 3kmph
  • 4 kmph
Show Solution

The Correct Option is D

Solution and Explanation

The correct answer is option (D):
3kmph

Let's break down this river flow problem. The key is understanding how the current affects the boat's speed.

* Upstream: When the boat travels against the current, the current slows it down.
* Downstream: When the boat travels with the current, the current speeds it up.

Let's use variables:

* Let 'x' be the speed of the river flow (in km/hr).
* The boat's speed in still water is 10 km/hr.

Therefore:

* Speed downstream (with the current) = 10 + x km/hr
* Speed upstream (against the current) = 10 - x km/hr

We know that Distance = Speed x Time, therefore Time = Distance / Speed.

* Time taken to travel downstream (91 km) = 91 / (10 + x) hours
* Time taken to travel upstream (91 km) = 91 / (10 - x) hours

The total time for the round trip is 20 hours. So:

91 / (10 + x) + 91 / (10 - x) = 20

To solve for 'x', we first need to get rid of the fractions. Multiply both sides of the equation by (10 + x)(10 - x):

91(10 - x) + 91(10 + x) = 20(10 + x)(10 - x)

Expanding the equation gives:

910 - 91x + 910 + 91x = 20(100 - x^2)

Simplifying:

1820 = 2000 - 20x^2

Rearranging:

20x^2 = 180

Dividing by 20:

x^2 = 9

Taking the square root of both sides:

x = 3 (We only consider the positive solution since speed cannot be negative).

Therefore, the speed of the flow of the river is 3 km/hr. This matches the correct answer.
Was this answer helpful?
0