Let $b$ represent the speed of the first boat, $s$ represent the speed of the second boat, and $r$ represent the speed of the river. Let $d$ be the distance between points A and B.
According to the problem statement:
$\Rightarrow d = 2(b + r)$ and $d = 3(b - r)$
Solving these equations simultaneously yields:
$\Rightarrow b + r = \frac{d}{2}$ and $b - r = \frac{d}{3}$
Subtracting the second equation from the first:
$\Rightarrow (b + r) - (b - r) = \frac{d}{2} - \frac{d}{3}$
$\Rightarrow 2r = \frac{3d - 2d}{6} = \frac{d}{6} \Rightarrow r = \frac{d}{12}$
Considering the time taken by the second boat:
$\frac{d}{s + r} + \frac{d}{s - r} = 6$
Substituting the value of $r = \frac{d}{12}$:
$\Rightarrow \frac{d}{s + \frac{d}{12}} + \frac{d}{s - \frac{d}{12}} = 6$
To simplify, multiply the numerator and denominator by 12:
Alternatively, multiply the entire equation by the least common multiple (LCM) for simplification:
Adjusting the numerator and denominator:
$\Rightarrow \frac{d(12)}{12s + d} + \frac{d(12)}{12s - d} = 6$
Multiplying both sides by $(12s + d)(12s - d)$:
$\Rightarrow 12d(12s - d) + 12d(12s + d) = 6(144s^2 - d^2)$
Simplification leads to:
$144ds - 12d^2 + 144ds + 12d^2 = 6(144s^2 - d^2)$
$\Rightarrow 288ds = 864s^2 - 6d^2$
Rearranging the terms to one side:
$\Rightarrow 144s^2 - 48ds - d^2 = 0$
Solving this quadratic equation for $s$ using the quadratic formula:
$s = \frac{48d + \sqrt{(48d)^2 + 4(144)(d^2)}}{2 \cdot 144}$
$= d\left(\frac{48 + \sqrt{48^2 + 4 \cdot 144}}{2 \cdot 144}\right)$
Further simplification yields:
$s = d\left(\frac{1}{6} + \frac{\sqrt{5}}{12}\right)$
Now, calculate the required value:
$\frac{d}{s + r} = \frac{d}{\frac{d}{6} + \frac{d\sqrt{5}}{12} + \frac{d}{12}}$
$\Rightarrow \frac{1}{\frac{1}{6} + \frac{\sqrt{5}}{12} + \frac{1}{12}} = \frac{1}{\frac{3 + \sqrt{5}}{12}} = \frac{12}{3 + \sqrt{5}}$
Rationalizing the denominator:
$\Rightarrow \frac{12}{3 + \sqrt{5}} \cdot \frac{3 - \sqrt{5}}{3 - \sqrt{5}} = \frac{12(3 - \sqrt{5})}{9 - 5} = \frac{12(3 - \sqrt{5})}{4}$
$\Rightarrow 3(3 - \sqrt{5})$
Thus, the correct option is (C): $\boxed{3(3 - \sqrt{5})}$