Question:medium

A block slides down a rough inclined plane with a constant velocity \(9.8\,\text{m s}^{-1}\). The coefficient of kinetic friction between the block and the surface is \(\dfrac1{\sqrt3}\). If the block is pushed up along the inclined plane from the bottom with a velocity \(9.8\,\text{m s}^{-1}\), then the distance travelled by the block before coming to rest is

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If a body moves down an inclined plane with constant velocity, \[ \boxed{\tan\theta=\mu.} \] When moving upward, both gravity and friction oppose the motion, so \[ \boxed{a=g\sin\theta+\mu g\cos\theta.} \]
Updated On: Jul 18, 2026
  • \(9.80\,\text{m}\)
  • \(2.45\,\text{m}\)
  • \(14.75\,\text{m}\)
  • \(4.90\,\text{m}\)
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The Correct Option is D

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