Question:medium
A block of mass 1 kg moving with velocity varies according to position as \( v = 2x^2 \). If the block goes from \( x = 0 \) to \( x = 5 \), find the work done by the block.
A block of mass 1 kg moving with velocity varies according to position as \( v = 2x^2 \). If the block goes from \( x = 0 \) to \( x = 5 \), find the work done by the block.
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When the velocity is given as a function of position, the work done can be calculated using integration. Work can also be found using the change in kinetic energy, \( W = \Delta K.E \).
Updated On: Apr 7, 2026
- zero
- 1250 J
- 1000 J
- 750 J
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The Correct Option is B
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