Question:medium

A ball is thrown at a speed of 20 m $s^{-1}$ at an angle of $30^{0}$ with the horizontal. The maximum height reached by the ball is ($g=10~ms^{-2}$)}

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Vertical component of velocity is $u \sin \theta$. Height depends only on this vertical component ($v_{y}^{2}/2g$).
  • 2 m
  • 3 m
  • 4 m
  • 5 m
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The Correct Option is D

Solution and Explanation

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